76=-16t^2+92t

Solution for 76=-16t^2+92t equation:

76=-16t^2+92t

We move all terms to the left:

76-(-16t^2+92t)=0

We get rid of parentheses

16t^2-92t+76=0

a = 16; b = -92; c = +76;
Δ = b2-4ac
Δ = -922-4·16·76
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-60}{2*16}=\frac{32}{32}
=1
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+60}{2*16}=\frac{152}{32}
=4+3/4
$